Question

3x^2-14x+8, is this factorable?

Answer 1

\[-b \pm \sqrt{b ^{2}-4ac}\div2a\]

Answer 2

a=3
b=-14
c=8
juz plug in d values
u ll gt d vale of roots of x

Answer 3

How do you simplify this, (3x^2-14x+8) / (2x-3)

Answer 4

yes it's factorable:

\[3x^2 -14x+8=> 3x^2 -12x-2x+8 = 3x(x -4) -2(x-4) =>(x-4)(3x-2)\]

simplifying it will give:

\[\frac{ (x-4)(3x-2) }{2x-3 }\]

and thats the limit

Answer 5

3x^2-14x+8, is this factorable yes = (3 x-2)(x - 4) as above