Question

Find the surface area of a square pyramid that has a base length of 14m and slant height of 19m

Answer 1

please help

Answer 2

\[A=a ^{2}+2a(\sqrt{\frac{ a ^{2} }{ 4 }+h ^{2}}\]
\[=14^{2}+2(14)(\sqrt{\frac{ 14^{2} }{4 }+19^{2}}\]
\[=196+28\times \sqrt{\frac{ 196 }{4 }+361}\]
\[=196+28(\sqrt410)\]
\[=196+28\sqrt{410}\]
=762.96(to 2 decimal places)

Answer 3

thank you @Mokeira

Answer 4

u welcome :)