solve x-y=1 for x(x-1-y) && substitute in the equation of the circle to obtain:
(1+y)2+2x(1+y)+y2+4y=-1
write the above quadratic equation in standard form and solve it to obtain
y=-2+sqrt(2)and y=-2-sqrt(2)
use x=1+y to find x
points of intersection:(-1+sqrt(2),-2+sqrt(2))and (-1-sqrt(2),-2-sqrt(2))

Question

solve x-y=1 for x(x-1-y) && substitute in the equation of the circle to obtain:
(1+y)2+2x(1+y)+y2+4y=-1
write the above quadratic equation in standard form and solve it to obtain
y=-2+sqrt(2)and y=-2-sqrt(2)
use x=1+y to find x
points of intersection:(-1+sqrt(2),-2+sqrt(2))and (-1-sqrt(2),-2-sqrt(2))

anonymous · Answer

@midhun.madhu1987 
can you help meee ?