What is the solution to the square root of 6x+1|end root| +1=x?

Question

cwrw238 · Answer

sqrt(6x + 1 ) + 1 = x
sqrt(6x+1) = x - 1

square both sides:

6x + 1 = ( x - 1)^2

now solve this quadratic equation

cwrw238 · Answer

can u continue from here?

anonymous · Answer

I got 6x-1=x^2-2x+1, added 1 to both sides adn then 2x to both sides and got 8x=x^2 +2. I know I need to isolate X but once I do, do I square both sides or do I make the equation equal 0 and then factor?

cwrw238 · Answer

make equation = 0

cwrw238 · Answer

x^2 - 8x + 2 = 0

anonymous · Answer

Do I factor?

cwrw238 · Answer

that will not factor.
use the quadratic formula 

x =  [-(-8) +/- sqrt (8^2 - 4* !* 2)]   / 2

cwrw238 · Answer

this will give you 2 solutions for x
check fo an extraneous solution by substituting back in the original equation