OpenStudy (anonymous):

What is 2^3/2 equal to?

3 years ago
OpenStudy (anonymous):

Too many math questions get posted around here without parentheses, that desperately need to have them. A couple of other answerers here have already pointed out the ambiguity in what you wrote. You can make it clear using the additional details feature. OK, that said, it looks like you meant 2^(5/2) - 2^(3/2), because (2^5)/2 - (2^3)/2 would be so much easier. But please, in the future, practice safe math -- use parentheses! Using the rule: a^(b+c) = (a^b)(a^c), 2^(5/2) - 2^(3/2) = 2^(1 + 3/2) - 2^(3/2) = 2^(3/2) (2 - 1) = 2^(3/2) = 2^(1 + 1/2) = 2 * 2^(1/2) = 2√2

3 years ago
OpenStudy (anonymous):

4

3 years ago
OpenStudy (anonymous):

3 years ago
OpenStudy (solomonzelman):

2^3 --- 2 or 2^3 / 2 ?

3 years ago
OpenStudy (jdoe0001):

$$\bf \cfrac{2^3}{2}?$$

3 years ago
OpenStudy (anonymous):

it is 4

3 years ago
OpenStudy (anonymous):

That's not one of the answer choices

3 years ago
OpenStudy (anonymous):

Let me post the answer choices, give me a second

3 years ago
OpenStudy (solomonzelman):

You didn't say if it is $$\normalsize\color{blue}{ 2^{3/2}}$$ or $$\normalsize\color{blue}{ 2^{3}/2}$$

3 years ago
OpenStudy (jdoe0001):

$$\Large a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad \sqrt[{\color{red} m}]{a^{\color{blue} n}}=a^{\frac{{\color{blue} n}}{{\color{red} m}}}$$

3 years ago
OpenStudy (anonymous):

It is 2^(3/2)

3 years ago
OpenStudy (solomonzelman):

then use the formula jdoe0001 posted

3 years ago
OpenStudy (anonymous):

It's not one of the answers

3 years ago
OpenStudy (anonymous):

3 years ago
OpenStudy (solomonzelman):

2^(3/2) = ²√ 2³ = √8

3 years ago
OpenStudy (solomonzelman):

Still not one of the choices ?

3 years ago
OpenStudy (anonymous):

It would be 2 to the square root of 8?

3 years ago
OpenStudy (anonymous):

$2\sqrt{8} ?$

3 years ago
OpenStudy (solomonzelman):

It is $$\normalsize\color{black}{ \sqrt[2]{8}}$$, which is the exact same thing as $$\normalsize\color{black}{ \sqrt{8}}$$

3 years ago
OpenStudy (anonymous):

Okay, thanks for showing me how to do it in the process :D

3 years ago
OpenStudy (anonymous):

You never fail to disappoint

3 years ago
OpenStudy (anonymous):

Wait

3 years ago
OpenStudy (anonymous):

Did I say that wrong

3 years ago
OpenStudy (anonymous):

You never fail to solve the question!

3 years ago
OpenStudy (solomonzelman):

you said, $$\normalsize\color{black}{ 2\sqrt{8}}$$ and it is not that, it is $$\normalsize\color{black}{ \sqrt[2]{8}}$$

3 years ago
OpenStudy (solomonzelman):

it is not $$\normalsize\color{black}{ 2\times\sqrt{8}}$$, just $$\normalsize\color{black}{ \sqrt{8}}$$

3 years ago
OpenStudy (anonymous):

its d

3 years ago
OpenStudy (solomonzelman):

no

3 years ago
OpenStudy (solomonzelman):

I gave you the answer, didn't I ?

3 years ago