Mathematics
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OpenStudy (anonymous):
FAN AND MEDAL!!
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OpenStudy (anonymous):
Determine the factors of x^2 - 12x - 20.
(x - 2)(x + 10)
(x - 10)(x + 2)
(x - 5)(x + 4)
Prime
OpenStudy (precal):
so factor this
look at the last term you have 20
list all factors of 20
OpenStudy (anonymous):
Negative twenty. ^^ And hang on. Let me think
OpenStudy (anonymous):
1,2,4,5,10
OpenStudy (anonymous):
@precal
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OpenStudy (precal):
1,20
2,10
4,5
OpenStudy (precal):
ok the minus in front of 20 means to subtract them
20-1
10-2
5-4
we only want positive results
OpenStudy (precal):
your middle number is a 12 does any of them produce a 12
OpenStudy (anonymous):
2 and 10
OpenStudy (precal):
10-2 is not 12
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OpenStudy (precal):
so when this happens we say it is prime and we can not factor it
OpenStudy (anonymous):
Oh okay thanks!!
OpenStudy (precal):
np
OpenStudy (anonymous):
One more if thats okay?
OpenStudy (precal):
ok, what do you have
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OpenStudy (anonymous):
This is A right?
Factor completely: -5k^2 + 20k - 30
-1(5k^2 - 20k + 30)
-5(k^2 - 4k + 6)
-5k(k^2 - 4k + 6)
-5(k^2 + 4k - 6)
OpenStudy (precal):
not quite because all of them also, have a in common to factor out
OpenStudy (precal):
so factor out a -5
OpenStudy (anonymous):
It would have to be B
OpenStudy (precal):
yes that would be correct
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OpenStudy (anonymous):
Thanks!!
OpenStudy (precal):
np
OpenStudy (anonymous):
Factor completely: 2x^2 - 6x - 36
2(x - 3)(x + 6)
2(x - 6)(x + 3)
(2x - 4)(x +9)
(2x - 9)(x + 4)
OpenStudy (anonymous):
Isnt this A
OpenStudy (precal):
can you close out this question and post a new thread, please?