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Mathematics 16 Online
OpenStudy (anonymous):

FAN AND MEDAL!!

OpenStudy (anonymous):

Determine the factors of x^2 - 12x - 20. (x - 2)(x + 10) (x - 10)(x + 2) (x - 5)(x + 4) Prime

OpenStudy (precal):

so factor this look at the last term you have 20 list all factors of 20

OpenStudy (anonymous):

Negative twenty. ^^ And hang on. Let me think

OpenStudy (anonymous):

1,2,4,5,10

OpenStudy (anonymous):

@precal

OpenStudy (precal):

1,20 2,10 4,5

OpenStudy (precal):

ok the minus in front of 20 means to subtract them 20-1 10-2 5-4 we only want positive results

OpenStudy (precal):

your middle number is a 12 does any of them produce a 12

OpenStudy (anonymous):

2 and 10

OpenStudy (precal):

10-2 is not 12

OpenStudy (precal):

so when this happens we say it is prime and we can not factor it

OpenStudy (anonymous):

Oh okay thanks!!

OpenStudy (precal):

np

OpenStudy (anonymous):

One more if thats okay?

OpenStudy (precal):

ok, what do you have

OpenStudy (anonymous):

This is A right? Factor completely: -5k^2 + 20k - 30 -1(5k^2 - 20k + 30) -5(k^2 - 4k + 6) -5k(k^2 - 4k + 6) -5(k^2 + 4k - 6)

OpenStudy (precal):

not quite because all of them also, have a in common to factor out

OpenStudy (precal):

so factor out a -5

OpenStudy (anonymous):

It would have to be B

OpenStudy (precal):

yes that would be correct

OpenStudy (anonymous):

Thanks!!

OpenStudy (precal):

np

OpenStudy (anonymous):

Factor completely: 2x^2 - 6x - 36 2(x - 3)(x + 6) 2(x - 6)(x + 3) (2x - 4)(x +9) (2x - 9)(x + 4)

OpenStudy (anonymous):

Isnt this A

OpenStudy (precal):

can you close out this question and post a new thread, please?

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