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Mathematics 19 Online
OpenStudy (anonymous):

simplify tan^2x/(cscx+1)

OpenStudy (larseighner):

Do you know the trig identity: \[\Large \tan^2\alpha + 1 = \sec^2\alpha \]

OpenStudy (anonymous):

yes sir

OpenStudy (larseighner):

Try \( \tan^2 = \sec^2x - 1 \) as the basis of a substitution.

OpenStudy (anonymous):

oops i messed up its supposed to be tan^3x over cscx+1

OpenStudy (anonymous):

i ended up with 2tan(x) thanks a lot !

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