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OpenStudy (anonymous):
hey plzz solve this for me
m^2 +4 = 4m @mathmale
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OpenStudy (xapproachesinfinity):
subtract 4m from both sides
you will have quadratic equation
you should know how to do it?
OpenStudy (anonymous):
cud u juts do and show me sir..i am confuseddd
OpenStudy (xapproachesinfinity):
\(\huge m^2-4m+4=0\)
OpenStudy (anonymous):
now???
OpenStudy (anonymous):
@xapproachesinfinity now what shud i do
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OpenStudy (xapproachesinfinity):
what is that look like to you?
OpenStudy (xapproachesinfinity):
\(\large (a-b)^2=a^2-2ab+b^2\)
OpenStudy (anonymous):
but i dont know how to apply i trie dit still didnt get it sir
OpenStudy (xapproachesinfinity):
well a=m and b=2
can you see it now?
OpenStudy (xapproachesinfinity):
\(\huge m^2-4m+4=m^2-2\times2m+2^2\)
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OpenStudy (anonymous):
sir just solvfe it plzz
i forogt the method
OpenStudy (xapproachesinfinity):
well we cannot give answers! i can guide there!
if you still stuck, this means you shouldn't take this class yet!
OpenStudy (anonymous):
hmmm :( just show me how to solve it plzzz...cuz i have a set of questions like this
OpenStudy (xapproachesinfinity):
\(\huge m^2-4m+4=(m-2)^2=0\)
the means that \(\huge m-2=0~ \\\huge m=2\)
that's you solution
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