how high is semi-elliptical arch of height 20 ft and span 80 feet at a distance of 15 ft from the the end?

Question

anonymous · Answer

substitute x=2.5in

       y = +sqrt%2816-x%5E2%29%2F2+

       y = +sqrt%28+16-%282.5%29%5E2+%29%2F2
      
       y = sqrt%289.75%29%2F2 = 1.5612495 dekafeet.

So the answer in feet is 15.612495.

anonymous · Answer

how do you get that??

anonymous · Answer

thank you for the answer but i want to know the process of it. thanks

anonymous · Answer

i put the process ill rewrite

anonymous · Answer

ok . thanks can u write it through the log process. i mean not input in computer or calculator. when i looked at it its like hard to understand.thanks

anonymous · Answer

*long process

anonymous · Answer

five equal squares are joined together to form a rectangle whose perimeter is 372cm. what is the area of each square