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if the point (2/3,y) on a unit circle what is y? a) 2/3 b)1/3 c)√5/3 d)4/9 please help!!!!!!
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please help me i can not get it wrong
|dw:1407979790098:dw|
y is going to be the height of that triangle. ANd you notice you have a right-angled triangle, so you can use the Pythagorean theorem
I drew 1 for the hypothenuse since you have a unit circle, and the radius in a unit circle is 1
so\[\frac{ 2 }{ 3 } ^{2}\] + \[y ^{2}\] = 1^2
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um yes, just to be sure write it as \(\large \left( \frac{2}{3}\right)^2\) All you have to do then is solve for \(y\) :)
so d
not quite
\[\left( \frac{2}{3}\right)^2+y^2=1^2\\ \frac{4}{9}+y^2 = 1\\ y^2=1-\frac{4}{9}=\frac{5}{9} \]
then square root both sides to find y
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