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Geometry 19 Online
OpenStudy (anonymous):

Ratios of Surface Area & Volume. Someone help. I'm confused on how to set it up.

OpenStudy (anonymous):

OpenStudy (mokeira):

the volume scale factor is \[16:2\] find the linear scale factor by finding cube root \[(\sqrt[3]{16}:(\sqrt[3]{2})\] now find the area scale factor by squaring \[(\sqrt[3]{16})^{2}:(\sqrt[3]{2})^{2}\] to get \[16^{\frac{ 2 }{3 }}:2^{\frac{ 2 }{3 }}\] \[\frac{ 16\frac{ 2 }{ 3 } }{ 2^{\frac{ 2 }{ 3 }} }=\frac{ 52 }{ x }\] cross multiply and simplify to get x=13

OpenStudy (mokeira):

hope you understood

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