Question

the difference of two numbers is 3 ; and three times the greater exceeds twice the less by 18 . find the numbers

Answer 1

let the numbers be x and y
\[x-y=3\]
\[3x=2y+18\]

\[x=3+y\]
substitute
\[3(3+y)=2y+18\]
solve for y
\[9+3y=2y+18\]
\[y=9\]

earlier on we found that
\[x=3+y\]
we can now find x
\[x=3+9=12\]

Answer 2

@keylaunie