Question

A stone at end of a string of length 1.50 m is whirled in a horizontal circle on a smooth surface. The speed of the stone is 0.8 ms^-1.

Answer 1

a) What is the angular velocity of the stone ?

Answer 2

@Abhisar

Answer 3

\(\huge \sf v=\omega r\\ \Rightarrow \huge \omega=\frac{0.8}{1.50}\)

Answer 4

Thanks Abhisar

Answer 5

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