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algebra 1/II question!! I need to factor this: 4y2-5y-4
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you cant
use quadratic formula
\[x=-b \pm \sqrt{b^2-4ac}/2a\]
4y^2-5y-4 Use quadratic formula y = (-(-5)±sqrt((-5)^2-4(4)(-4)))/2(4) =(5±sqrt(25+64)/8 =(5±sqrt(89)/8 Source: http://www.mathskey.com/question2answer/
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