Question

Consider the circle of radius 5 centered at (0,0). Find an equation of the line tangent to the circle at the point (3,4) in slope intercept form.

Answer 1

Slope , m = (4-0)/(3-0) =4/3
Perpendicular slope =-3/4
Equation of tangent
y=(-3/4)x+c
point(3,4)
4=(-3/4)(3)+c
c=4+(9/4)
=25/4
y=(-3/4)x+25/4

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