I need someone to take me step by step...please Factor \[x ^{3}-3x ^{2}-4x+12\]
what have you tried so far
ok..this is what i got finally (x+12)(x-2)(x+2)(x+1)
\(\Large \sf\color{blueviolet}{before~ you~think ~about ~anything,~ think~ about ~easier~ways}\)
i think there is a mistake what did you do?
\[x ^{3}-3x ^{2}-4x+12\] \[x(x ^{2}-3x-4)+12\] I know that is where i went wrong
but i dont know how to go about it
this one you could group
thats a very good mistake :)
Do you realize that!
lol @ganeshie8
how do I group @xapproachesinfinity
not exactly a mistake, but a very good attempt which wont work !
you have x^2 common btw the first two and 4 common for the left over you will have (x-3) as a common factor
ok..let me try and show you all
okay!
x(x ^{2}-3x-4)+12 what could you do with this! seems you gone completely off the road xD
\[x ^{2}(x-3)-4(x-3)\] is this right then \[(x ^{2}-4)(x-3)=(x-2)(x+2)(x-3)\]
See very easy^_^
lol...it felt so right but looked soooo wrong @xapproachesinfinity @ganeshie8
yaaaaay!!!!!!! thank you allllllllll :) :) :) :) :)
Yay!!! i enjoy your enjoyment^_^ there is one that i posted some time ago you wanna go ahead an try?
definately!!
okay give a moment!
\(\Large \sf\color{blueviolet}{x^4-12x^3+59x^2-138x+130}\)
i posted this before! it is a hard one though but try for yourself and see
it looks challenging....let me try
@ikram002p san^_^
yeah! go for it! if you give up you can look at the solution in my posts ^_^
san in what accent :o
that's Japanese^_^ i learned some japanese words hehe
ok..this will take me long!...i will post my answer next time I log in @xapproachesinfinity and show you how i will have done it so that you check if i will have messed up anywhere
i thought so :P i know that word , but i thought its also ur accent san for girl , kun for boy right ? or sama something like this
okay @Mokeira, anytime you ready ^_^
wow you know those too lol sama is a more dignifying word only used for someone that older than you the other you got them right^_^
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