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A bucket contains 5 yellow and 7 red balls. If 2 balls are selected randomly without replacement, what is the probability that they will both be yellow?
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first withdrawal: Probabilty of a yellow = 5/12 that leaves 11 balls so what is the probability of another yellow being withdrawn?
4/11
right now for independent events the probabilities are multiplied so the required probability is 5/ 12 * 4/11
=20/132
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right or you can simplify it by dividing top and bottom by 4 to give 5/33
Oh thanks... Dint know its that EASY!
Thanks I got it right on my assessment.
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