Question

hyperbola questions giving medals for help.

Answer 1

with asymptotes at
\[y=\frac{ 3 }{ 2 }x+2\]
and\[y=-\frac{ 3 }{ 2 }x+4\]

so the center is at \[(\frac{ 2 }{ 3 },3 )\]

Answer 2

I need help finding the focal length and eccentricity

Answer 3

STRIP lol jk

Answer 4

will save that for later

Answer 5

i suck at math so cant help ya

Answer 6

oh wait i think i know, i didnt see it says it has a vertical transverse axis...

Answer 7

ok i solved the eccentricity its
\[\frac{ \sqrt{13} }{ 3 }\]

still need help finding the focal length

Answer 8

i thought it would be sqrt(13) but its not accepting that as the right answer..

Answer 9

welp **** guessed it and got it wrong

Answer 10

gonna have to generate a new problem and start over now. But if anyone finds how to get the focal length thats all i need help with.

Answer 11

have an idea i think will work