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Determine the equation of a line (in standard form ax + by = c) (-1,3) (2,-4)
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firsty find the gradient using to points, step 1: \[m=\frac{ y2-y1 }{ x2-x1 }\] then: step2: \[y-y1 = m(x-x1) \] step3: make y the subject. your straight line equation is done. \[y = ...\]
sorry i forgot for step 2: you could use (x1,y1) = (-1,3) or (2,-4)
In step 3, express the equation in the form: Ax + By = C to put it in the standard form.
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