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Geometry
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Given the diagram of parallelogram LMNO, solve for r.
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4r = 3s --> eqn 1, we'll have s = 4r/3 2t+10 = 3t - 15 Hence, t = 25 2t + 10 = 3t - 15 = 60 from summation angle of quadrilateral equals 360, we have (2t + 10) + (3t - 15) + 4r + 3s = 360 60 + 60 + 4r + 3(4r/3) = 360 120 + 8r = 360 8r = 240 r = 30
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