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vectors a and b have magnitudes 3 and 5. The angle between the vectors is 130 degrees. determine the magnitude of the vector -a x 4b (cross product) the answer is 46 but I don't know how to get to that answer
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let a = (3,0) let b= (5cos(130),5sin(130))
might as well make them 3D, tack on a ,0 for the z component
take the determinant: x y z x y -3 0 0 -3 0 20cos(130) 20sin(130) 0 20cos(130) 20sin(130) (0,0,-60sin(130)) the magnitude should be 60sin(130)
45.96
thanks a lot!
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