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x2 + 18x + 76 = 0 Which of the following is the first correct step to write the above equation in the form (x - p)2 = q, where p and q are integers?
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Okay, I'm going to change the equation to just\[x^2+18x+76\]
18x is the middle term, which means that the coefficient we're going to halve is 18.
\[18\div2=9\]
\[9^2=?\]
\[x^2+18x+76=0\]
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\[x^2+18x+76+???=0+???\]
add five to both sides\[x^2+18x+81\]
ok
thanks
No problem.
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