What are the first five terms of the sequence defined by asub1=-1 and asubn=1/3(asubn-1)

(sub just means it should be a subscript)

Question

What are the first five terms of the sequence defined by asub1=-1 and asubn=1/3(asubn-1)

(sub just means it should be a subscript)

solomonzelman · Answer

$\large\color{blue}{ a_1=-1,~~~~a_n=1/3(a_n-1)\huge\color{white}{ \rm    │  }}$  like this ?

anonymous · Answer

yeah

solomonzelman · Answer

Well, you know the first term already... WAIT... 

$\large\color{blue}{ a_1=-1,~~~~a_n=1/3(a_{n-1})\huge\color{white}{ \rm    │  }}$

-1 is part of the sub , in other words the common ratio is 1/3  right ?

anonymous · Answer

yeah, sorry.
misread it the first time

solomonzelman · Answer

Okay, so with the common ratio of 1/3, you will get the denominator increasing...

1/1
1/3
1/9
1/27
1/81

for the first 5 term.

And on....

anonymous · Answer

ok, thank you!

solomonzelman · Answer

Anytime !