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What is the range of:
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\[f ^{-1}\] when \[f(x)=\sqrt{x-5}\]
And first, find \[f ^{-1}\]
range of the inverse or of f(x) ?
Yes
But first find the inverse of f(x)
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y = \(\sqrt{x-5}\) \(y^2 = x - 5\) x = \(y^2 + 5\) \(f^{-1} (x) = x^2 + 5\) Domain of f equals range of inverse of f. Find the domain of f.
I don't know how do do that part
I will draw it...
domain of f(x) = All real numbers 4<?
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