Question

f(x)=x^2+3x+4. determine the x value if
y=2
and
y=8

Answer 1

x²+3x+4=2
x²+3x+2=0
(x+1)(x+2)=0
x = ?

Answer 2

finish it.. I am going to Kroger now....

Answer 3

For y=2
x²+3x+4=2
x²+3x+2=0
(x+1)(x+2)=0
x= -1, -2

For y=8
x²+3x+4=8
x²+3x-4=0
(x-1)(x+4)=0
x= 1, -4

Answer 4

thank you vary much i get ti now