Question

(1+2i)(2-3i)/(2-i)(3+2i) how do I solve this? :)

Answer 1

what do you mean by 'solve'?

Answer 2

(1+2i)(2-3i)/(2-i)(3+2i)
=(2-3i+4i-6i^2)/(6-3i+2i-2i^2)
=(2+6+i)/(6+2-i)
=(8+i)/(8-i)
now multiply by
(8+i)/(8+i)
then simplify

Answer 3

See the attachment.