The following is a report of defective parts reported by inspectors in 3 electronic factories:
Brookline= 3 per 10,000
Brookville= 5 per 100,000
Brooklyn= 13 per 1,000,000
Which of the following best expresses the portion of defective parts in three factories combined:
(A) 5 per 10,000
(B) 66 per 10,000
(C) 66 per 100,000
(D) 93 per 1,000,000
(E) 363 per 1,000,000

Question

The following is a report of defective parts reported by inspectors in 3 electronic factories:
Brookline= 3 per 10,000
Brookville= 5 per 100,000 
Brooklyn= 13 per 1,000,000
Which of the following best expresses the portion of defective parts in three factories combined:
(A) 5 per 10,000
(B) 66 per 10,000
(C) 66 per 100,000
(D) 93 per 1,000,000
(E) 363 per 1,000,000

anonymous · Answer

First, u have to make everything into the same turns because how are u suppose to solve something when everything is different?

anonymous · Answer

So i made everything into millions. It would be 300 per 1,000,000 50 per 1,00,00 and then 13 per 1,00,00. You would then just need to add everything up, and you would get your answer.

anonymous · Answer

Thank you! Wow that was a lot easier than i thought, it's just like adding fractions together!

anonymous · Answer

Your welcome!