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Calculus A help needed
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x f(x) f'(x) f''(x) 0 1 2 4 2 5 0 1 4 11 6 3
Show there is a point c in (0,2) with f'(c) < 0
Assuming \(f(x)\) is continuous and differentiable on [0,2] and (0,2), respectively, you can apply the mean value theorem: \[f'(c)=\frac{f(2)-f(0)}{2-0}=\frac{1-5}{2}<0\]
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