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Sin x cos x- sin^2 x= 0
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57.3 plusorminus 2 pi n
How do you solve by factoring?
\[\large{\sin x \cos x - \sin^2 x = 0}\] \[\large{\implies \sin x(\cos x - \sin x) = 0}\] Now: \[\large{a\times b = 0}\] \[\large{\implies a = 0 \ or \ b = 0}\]
Get it ?
I'm still a little confuse how you got that
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\[ \sin x = 0 \quad \text{or}\quad \cos x - \sin x = 0 \]
\[ \color{red}{\sin x} \color{blue}{\cos x} - \color{purple}{\sin^2 x }= \color{red}{\sin x} \color{blue}{\cos x} - \color{red}{\sin x} \color{blue}{\sin x} =\color{red}{ \sin x} (\color{blue}{\cos x - \sin x}) \]
So would that be the answer?
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