Question

change to vertex form:FRACTION

y= 1/5 (2x^2 -4x +7 )

Answer 1

Posting from the previous question:


y = ⅕(2x²-4x+7) at first I would factor out of 2.
y = ⅖(x²-2x+3½)
And now, you have inside the parenthesis 2½ more than what you want to make the parenthesis a perfect square
Follow this carefully.
y = ⅖(x²-2x+1+2½)
y = ⅖(x²-2x+1)+(2½×⅖)
y = ⅖(x²-2x+1)+({5/2}×{2/5})
y = ⅖(x²-2x+1)+(1)
y = ⅖(x²-2x+1)+1
y = ⅖(x-1)²+1

Answer 2

opens up.
stretched horizontally.
minimum point at (1,1)