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Given the function f(x) = 3x + 1, evaluate f(a + 1).
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you mean f(x+1) ?
\(\normalsize\color{blue}{ f(x) = 3x + 1\LARGE\color{white}{ \rm │ }}\) and \(\normalsize\color{green}{ f(x+1) = 3(x+1) + 1= ?\LARGE\color{white}{ \rm │ }}\) you tell me
well, f(a+1) would be the exact same thing, BUT with ` a ` instead of ` x ` .
its the same thing as f(x)
well, you are plugging `a+1` EVERYWHERE for x,
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yes.
my answers to pick is 3a + 1 3a + 2 3a + 4
\(\normalsize\color{black}{ f(a+1) = 3(a+1) + 1}\) \(\normalsize\color{black}{ f(a+1) = 3a+3 + 1}\) \(\normalsize\color{black}{ f(a+1) = ??}\) which option do you pick ?
you have to distribute
you have to add like terms on the right side.
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okay
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