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Please Help me !! Its simple question though but i don't know how to solve it ??
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How to write \(\large \bf 6x^2+5xy-4y^2=0\) in another form or equation?
basically, just factor out
Like i have to convert in this :- \[\large \bf (2x-y)(3x+4y)\] i can't judge out that how to obtain this equation ?
@cwrw238 help me!!
@SolomonZelman
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well, you just did it, no ?
well this is the way i do these - you need to look at factors of the first coefficient and the last that is 6 and -4 6 could be 6 * 1 or 2 * 3 and -4 could be -4*1 or 4 * -1 , or -2 * 2 now we have to find a way to combine these factor so as to get the middle coefficient +5
solomon, i do it many times but i don't get this equation
i draw up columns; |dw:1408387576129:dw|
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