Question

Find the value of x and y.

Answer 1

I would suggest posting problems one by one....

Answer 2

for (C) the missing side is AD and the missing measurement is 2

then for D

\[\frac{x}{8} = \frac{2}{x} \]

cross multiply and you get

\[x^2 = 16\]

solve for x

Answer 3

For (D) would it be: \[\frac{y }{ 3 } = \frac{ 8 }{ x }\]

Answer 4

@campbell_st

Answer 5

yes.... but the need the value of x from part c...

you should have found x = 4

so you are looking at

\[\frac{y}{3} = \frac{8}{4}\]

Answer 6

Alright. Thank you. You were a lot of help.