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Mathematics 21 Online
OpenStudy (anonymous):

simplify the expression and solve the equation

OpenStudy (anonymous):

\[\frac{ z^2-3z+2 }{z^2+3z-4 ? }* \frac{ z^2+6z+8 }{z^2-4 ? }\]

OpenStudy (anonymous):

@Dbzfan836 can u help

OpenStudy (dbzfan836):

is this algebra?

OpenStudy (anonymous):

yes

OpenStudy (dbzfan836):

@Broskishelleh

OpenStudy (dbzfan836):

this is my bother, and an excellent algebra guy. hes a yr older than me

OpenStudy (anonymous):

\[\frac{ z^2-3z+2 }{z^2+3z-4 }* \frac{ z^2+6z+8 }{z^2-4 }=z \]

OpenStudy (anonymous):

forgot to put the z at the end. ok cool. thanks

OpenStudy (dbzfan836):

k he is writing it out now

OpenStudy (dbzfan836):

hes doin the math and is almost done

OpenStudy (broskishelleh):

z = 1

OpenStudy (dbzfan836):

there u go

OpenStudy (anonymous):

i have to show work tho

OpenStudy (broskishelleh):

Ah, ok give me a second

OpenStudy (anonymous):

sorry and thank you

OpenStudy (dbzfan836):

srry its taking so long. he was using his head for some of the calc

OpenStudy (anonymous):

no no its completely fine

OpenStudy (broskishelleh):

Factor the numerator. (z−2)(z−1)/z2+3z−4 ⋅ z2+6z+8/z2−4=z Factor the denominator. (z−2)(z−1)/(z+4)(z−1) ⋅ z2+6z+8/z2−4=z Reduce the expression by canceling out all common factors from the numerator and denominator. z−2/z+4 ⋅ z2+6z+8/z2−4=z Factor the numerator. z−2/z+4 ⋅ (z+4)(z+2)/z2−4=z Factor the denominator. z−2/z+4 ⋅ (z+4)(z+2)/(z+2)(z−2)=z Reduce the expression by canceling out all common factors from the numerator and denominator. z−2/z+4 ⋅ 1(z+4)/z−2=z Cancel the common factor of (z+4) from the denominator of the first expression and the numerator of the second expression. (z−2) ⋅ 1/z−2=z Reduce the expression by canceling out all common factors from the numerator and denominator. 1=z

OpenStudy (broskishelleh):

I have finished

OpenStudy (broskishelleh):

@aballer101 Please come back

OpenStudy (anonymous):

holy crap your a life saver!! THANK YOU

OpenStudy (broskishelleh):

Welxome, tag meh if ya need help

OpenStudy (anonymous):

okay once again thanks

OpenStudy (broskishelleh):

np

OpenStudy (dbzfan836):

that is the power of my brother. NEVER MESS WITH MATHEMATICS

OpenStudy (broskishelleh):

Just get in the Freakin Car! https://www.youtube.com/watch?v=ZLpgagKwJuI @aballer101

OpenStudy (anonymous):

lmaoo im subscribing to that channel

OpenStudy (dbzfan836):

NOOOO CHARLIE! https://www.youtube.com/watch?v=Fu2DcHzokew

OpenStudy (broskishelleh):

Ya like it?

OpenStudy (anonymous):

i have one more question if u dont mind me asking

OpenStudy (broskishelleh):

Ok, go ahead

OpenStudy (anonymous):

ya its funny

OpenStudy (anonymous):

okay im gonna close this one and post it.. that way i can give u another medal haha

OpenStudy (broskishelleh):

Ok

OpenStudy (broskishelleh):

Tag meh

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