simplify the expression and solve the equation
\[\frac{ z^2-3z+2 }{z^2+3z-4 ? }* \frac{ z^2+6z+8 }{z^2-4 ? }\]
@Dbzfan836 can u help
is this algebra?
yes
@Broskishelleh
this is my bother, and an excellent algebra guy. hes a yr older than me
\[\frac{ z^2-3z+2 }{z^2+3z-4 }* \frac{ z^2+6z+8 }{z^2-4 }=z \]
forgot to put the z at the end. ok cool. thanks
k he is writing it out now
hes doin the math and is almost done
z = 1
there u go
i have to show work tho
Ah, ok give me a second
sorry and thank you
srry its taking so long. he was using his head for some of the calc
no no its completely fine
Factor the numerator. (z−2)(z−1)/z2+3z−4 ⋅ z2+6z+8/z2−4=z Factor the denominator. (z−2)(z−1)/(z+4)(z−1) ⋅ z2+6z+8/z2−4=z Reduce the expression by canceling out all common factors from the numerator and denominator. z−2/z+4 ⋅ z2+6z+8/z2−4=z Factor the numerator. z−2/z+4 ⋅ (z+4)(z+2)/z2−4=z Factor the denominator. z−2/z+4 ⋅ (z+4)(z+2)/(z+2)(z−2)=z Reduce the expression by canceling out all common factors from the numerator and denominator. z−2/z+4 ⋅ 1(z+4)/z−2=z Cancel the common factor of (z+4) from the denominator of the first expression and the numerator of the second expression. (z−2) ⋅ 1/z−2=z Reduce the expression by canceling out all common factors from the numerator and denominator. 1=z
I have finished
@aballer101 Please come back
holy crap your a life saver!! THANK YOU
Welxome, tag meh if ya need help
okay once again thanks
np
that is the power of my brother. NEVER MESS WITH MATHEMATICS
Just get in the Freakin Car! https://www.youtube.com/watch?v=ZLpgagKwJuI @aballer101
lmaoo im subscribing to that channel
Ya like it?
i have one more question if u dont mind me asking
Ok, go ahead
ya its funny
okay im gonna close this one and post it.. that way i can give u another medal haha
Ok
Tag meh
Join our real-time social learning platform and learn together with your friends!