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Mathematics 21 Online
OpenStudy (anonymous):

Frequency, probability distribution... please help

OpenStudy (anonymous):

OpenStudy (anonymous):

I think it will be 60%

OpenStudy (anonymous):

Between 75 and 90 are 12 students. 12/20 total would be .6 so I assume 60% I'm not sure though

OpenStudy (anonymous):

count then number of students that scored in that range,then divide by 20

OpenStudy (anonymous):

yeah, what you said

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