Question

Factor 3x2 - 6x - 9 completely.

3(x - 1)(x + 3)

3(x + 1)(x - 3)

(3x + 1)(x - 3)

(3x +1)(x - 3)

Answer 1

Compare it with : \(ax^2 + bx + c\)

You will have : a = 3, b = -6 and c = -9

Answer 2

Always firstly you multiply a with c..

Can you tell me what will you get for \(a \times c\) = ??

Answer 3

I need your cooperation @andy11

Answer 4

sorry i had to do somthing. it would = -27

Answer 5

@waterineyes

Answer 6

So, here is the actual task now..

You have to find factors of -27, so that you get b ie -6..

Answer 7

Tell me what will be the two numbers if you multiply them you get -27 and if you add them you get -6??

Answer 8

Getting my point??

Answer 9

3

Answer 10

yeah im getting it sorry im just a little slow

Answer 11

Take your time, I can surely wait..

Answer 12

You have to choose two numbers..

Answer 13

Like I choose two numbers as : 1 and -27..

Here, multiplication will be give my -27 but the sum is not equal to -6 as :
\(1+( - 27) = -26\)