Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

Factor 3x2 - 6x - 9 completely. can some one just check my anser please

OpenStudy (anonymous):

i got 3(x+1)(x-3)

OpenStudy (anonymous):

That is correct

OpenStudy (anonymous):

or at least what i got too :P

OpenStudy (anonymous):

ok thanks you hope we are right (:

OpenStudy (anonymous):

@jdoe0001 what do you think?

OpenStudy (jdoe0001):

\(\large 3x^2 - 6x - 9\implies \begin{array}{cccllll} 3(x^2&-2x&-3)\\ &\uparrow &\uparrow \\ &-3+1&-3\cdot 1 \end{array}\) thus, is correct :)

OpenStudy (anonymous):

so my anser was correct?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!