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I have a few questions I need help with involving limits and continuous functions. Since they all have equations it will take me a minute or two to type all the equations up and post!
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find the value of c such that \[\lim_{x \rightarrow c ^{+}} \frac{ 6 }{ (x-2)(7-x)}=-\infty\]
why dont you graph f(x) = 6 / [ (x-2)(7-x)] first
c = 7 works
The expression becomes infinity when the denominator gets to zero. There are two values of x that will make the denominator zero. Which value when approached from the left will yield NEGATIVE infinity?
I meant "approached from the right"
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