Question

help please.
How can i writef(x)= 3x^2-6x+1 in the form f(x)=a(x-b)^2+c

Answer 1

you can use either method:
completing the square
factoring

Answer 2

your final answer would be 3(x-1)^2-2

Answer 3

3x^2-6x+1
3(x^2-2x)+1
3(x^2-2x+1-1)+1
3(x^2-2x+1)-3+1
3(x-1)^2-2

Source: http://www.mathskey.com/question2answer/

Answer 4

thanks fpr the help

Answer 5

\(ax^2+bx+c=0\iff a(x+\frac{b}{2a})^2=-c+a(\frac{b}{2a})^2\)