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Algebra 21 Online
OpenStudy (anonymous):

Log2 4x=5

OpenStudy (imstuck):

This is\[\log _{2}(4x)=5\]right?

OpenStudy (imstuck):

I'm assuming it is, so I will continue on here...

OpenStudy (imstuck):

This could be rewritten as\[2^{5}=4x\]

OpenStudy (imstuck):

Since\[2^{5}=32\]you have 32=4x. Now solve for x.

OpenStudy (imstuck):

Easy now, right?

OpenStudy (imstuck):

Remember this rule:\[\log _{a}(b)=x-->a ^{x}=b\]

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