Question

3x+2y=2, -2y+y=8

Answer 1

Is the question to find x?

Answer 2

Solve the following system:
\[3 x+2 y = 2 \]\[-y = 8 \]Multiply equation 2 by -1:
\[3 x+2 y = 2 \]\[0 x+y = -8 \]Subtract \(2 ×\) (equation 2) from equation 1:
\[3 x+0 y = 18 \]\[0 x+y = -8 \]Divide equation 1 by 3:
\[x+0 y = 6\]\[0 x+y = -8 \]Collect results:

Answer 3

Which leaves you with...?