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Algebra
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Log2 4x=5 solve this step by step please
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Is the Log2 getting multiplied by 4x or is 2 in Log2 like the base of log 2? Assuming Log base 2 to be a more logical assumption.. 1) 2^5=4x I just moved things around to get rid of Log back into exponents. 2) 2^5 = 32 3) 32=4x now divide by 4 4) x=8
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