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What are the solutions of 2x2 + 8x = -26? A) -2 ± 3 i B) -2 ± i C) 2 ± 6 i D) -3 ± 2 i
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1) divide all by \(2\) what do you get ?
i mean starting \[2x^2 + 8x = -26\]divide all by \(2\)
x1+x2=-b/a
x1.x2=c/a
ax²+bx+c
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x^2 + 4x = -13 @satellite73
k good only two more steps what is half of \(4\) ?
2
x1+x2=-4 so only can be A or B
right we go right from \[x^2+4x=-13\] to \[(x+2)^2=-13+2^2\] or \[(x+2)^2=-9\]
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9+4=13 so its A)
then \[x+2=\pm\sqrt{-9}\\ x+2=\pm3i\\ x=-2\pm3i\]
so it would be A (: @satellite73 @RaphaelFilgueiras
yes
thank you both so so much
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yw from us both
yw
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