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Evaluate the expression without using a calculator. (Sketch a right triangle).
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\[\tan (\arccos \frac{ \sqrt{2} }{ 2 })\]
same as before
|dw:1408508386087:dw|
find the other side you can do it in your head \[2^2-\sqrt2^2=4-2=2\]
method 2 know tha t \[\cos(\frac{\pi}{4})=\frac{\sqrt2}{2}\] and that \[\tan(\frac{\pi}{4})=1\]
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APologies. I'm just trying to really understand this. Maybe, I'm thinking about it too much.
yes you are thinking way too much i think then again if you have not seen trig for a while, who can remember all this stuff?
Then again, the massive amount of Trig. and Calculus rust. Yeah, I haven't seen any of this for a good year.
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