I am really struggling re gradients of a straight line, please someone help!
Q. Write down the gradient, m, for each of these straight lines:
1) y= 3-3x
ii) y= 2+x/3
iii) 3x+5y-8=0
iv) 2y+3x=0
v) 5x-4y-12=0
vi) 7x+6y-18=0
vii) 5x-2y/3-1=0
If someone could explain to me how this is done I would really appreciate it, thanks in advance.

Question

I am really struggling re gradients of a straight line, please someone help!
Q. Write down the gradient, m, for each of these straight lines:
1) y= 3-3x
ii) y= 2+x/3
iii) 3x+5y-8=0
iv) 2y+3x=0
v) 5x-4y-12=0
vi) 7x+6y-18=0
vii) 5x-2y/3-1=0
If someone could explain to me how this is done I would really appreciate it, thanks in advance.

anonymous · Answer

Y=MX+C   in which the M stands for the Gradient and the C for the Y intercept.
Rearrange all of the above questions into the structure Y=MX + C by isolating Y.
The coefficient of X is the Gradient 
E.g 
Question one is already arranged , coefficient of X is -3. Thus -3 is the answer
iii) 3x+5y-8=0 Rearranges to  5Y= 8-3x thus Y=8/5 - (3/5 x) coefficient of X is -3/5 and thus -3/5 is the answer

anonymous · Answer

Yes, thanks a ton :D