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A particle projected from ground takes time 't1' to reach 15/16 H height and time 't2' to cover rest of distance to the ground. If 'H' is the maximum height attaine. please find the ratio t1: t2
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projected from the ground then \[X = \frac{ 1 }{ 2 } a t ^{2}\] \[t=\sqrt{\frac{ 2 X }{ a }}.\] x for t1 = 15/16 H x for t2 = 17/16 H Thus divide them and symbols will be cancelled.
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