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hii can anyone help me with this question? prove that (sec x - tan x)(cosec x + 1) is equivalent to cot x
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try converting LHS to sin's and cos's and simplify
might be a bit long-winded but this often works
i'll start you off i'll write c for cos x and s for sinx (cos i'm lazy)
replace cosine by \(a\) and sine by \(b\) and multiply \[(\frac{1}{a}-\frac{b}{a})(\frac{1}{b}+1)\]
yea thats good idea
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\[(\frac{ 1 }{ cosx} - \frac{ sinx }{ cosx}) (\frac{ 1 }{ sinx } + 1)\] i'm not able to continue
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