Question

hii can anyone help me with this question?
prove that (sec x - tan x)(cosec x + 1) is equivalent to cot x

Answer 1

try converting LHS to sin's and cos's and simplify

Answer 2

might be a bit long-winded but this often works

Answer 3

i'll start you off i'll write c for cos x and s for sinx (cos i'm lazy)

Answer 4

replace cosine by \(a\) and sine by \(b\) and multiply
\[(\frac{1}{a}-\frac{b}{a})(\frac{1}{b}+1)\]

Answer 5

yea thats good idea

Answer 6

\[(\frac{ 1 }{ cosx} - \frac{ sinx }{ cosx}) (\frac{ 1 }{ sinx } + 1)\]
i'm not able to continue