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Let f(x) = x2 - 16. Find f-1(x).
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function is not one to one and does not have an inverse
you can solve \[x=y^2-16\] for \(y\) in two steps, but you will not get a function
\[x=y^2-16\\ x+16=y^2\\ \pm\sqrt{x+16}=y\]
the \(\pm\) tells you it is not a function
Thats what i just found out...thanks good sir!
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@satellite73 is too smart for us all hail satellite
The answer is sqrtx + 16 for future use
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