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Mathematics 10 Online
undeadknight26 (undeadknight26):

Let f(x) = x2 - 16. Find f-1(x).

OpenStudy (anonymous):

function is not one to one and does not have an inverse

OpenStudy (anonymous):

you can solve \[x=y^2-16\] for \(y\) in two steps, but you will not get a function

OpenStudy (anonymous):

\[x=y^2-16\\ x+16=y^2\\ \pm\sqrt{x+16}=y\]

OpenStudy (anonymous):

the \(\pm\) tells you it is not a function

undeadknight26 (undeadknight26):

Thats what i just found out...thanks good sir!

OpenStudy (acxbox22):

@satellite73 is too smart for us all hail satellite

undeadknight26 (undeadknight26):

The answer is sqrtx + 16 for future use

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