Question

What value is a discontinuity of x squared plus 8 x plus 4, all over x squared minus x minus 6? @antonio_xx2 @e.mccormick @quickstudent @FibonacciChick666 @myininaya @help123456 @helpmeplzzzzz! @dan815 @phi @Pi123

Answer 1

@dan815

Answer 2

\[\frac{ x^{2} + 8x + 4 }{ x^{2} - x - 6 }\]
This will help @dan815 @abb0t

Answer 3

so what value(s) of x make the bottom go haywire?

Answer 4

factor.

Answer 5

but yes, you factor to get to that point

Answer 6

I factor the equation on top it is hard please help

Answer 7

just factor the bottom to strat

Answer 8

I did and I got (x - 3) (x + 2)

Answer 9

Good!

Answer 10

now, when does that make the bottom a problem? for which x values?

Answer 11

But what is the right factors for the top

Answer 12

im sorry but im bad at those kind of problems, so i dont think ill be able to tell you. goodluck though!

Answer 13

the top does not factor nicely. so you don't have to factor at all
(it matters only if its factors match one of those in the bottom)

Answer 14

for the top, you want something that multiplies to 4 but adds to 8, which isn't possible so you have to complete the square, but you don't need the top here

Answer 15

So what is the answer to my question @FibonacciChick666 ?

Answer 16

any x value that causes a divide by 0

Answer 17

It is asking What value is a discontinuity vaule

Answer 18

things that make the bottom go haywire ie =0

Answer 19

so, what makes the bottom =0?

Answer 20

So the answer would be x = -2 or 2

Answer 21

put that in and see if it works, does it?

Answer 22

how did you get +2 ?

Answer 23

here is a graph, to show what's going on

Answer 24

What value is a discontinuity of x squared plus 8 x plus 4, all over x squared minus x minus 6?

x = -1

x = -4

x = -3

x = -2
I don't know This is the whole question @FibonacciChick666 @phi

Answer 25

well, check it for us then. Input the x value and see if you get zero or not

Answer 26

you found
***I did and I got (x - 3) (x + 2)***

what would make (x - 3) (x + 2) =0 ?

Answer 27

do you see if x is -2, then
(x - 3) (x + 2) would be (-2-3) (-2 + 2) = -5*0 = 0
or if x = 3 you would get
(3-3)(3+2) = 0 * 5 = 0

so those are your discontinuities

Answer 28

So the answer is -2 right?

Answer 29

to solve
(x - 3) (x + 2) =0

you make it two separate problems
x-3= 0 and x+2 =0
we get
x= 3 and x = -2 (if you know how to solve these equations)

Answer 30

There are two answers. But you only have to pick the one they listed.

Answer 31

-2 is the right answer @phi

Answer 32

is -2 one of the answers?

Answer 33

Yes

Answer 34

Thanks for the help but, I can only give one person a medal and I will Fan the other