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Mathematics 11 Online
OpenStudy (anonymous):

Find the solution sets of each equation if the replacement sets are A=(4,5,6,7,8) and B= (9,10,11,12,13) Problem is 5a-9=26

OpenStudy (fibonaccichick666):

I've never seen the term replacement sets, can you explain that?

OpenStudy (anonymous):

This is my first time seeing this also.. I Don't understand what they mean by this, I mean wouldn't you add 9 to each area?

OpenStudy (fibonaccichick666):

yea, so to solve for a that's the first step.

OpenStudy (anonymous):

Now what about b? lol

OpenStudy (fibonaccichick666):

huh?

OpenStudy (fibonaccichick666):

I was just solving 5a-9=26

OpenStudy (anonymous):

Sorrry, I'm like so lost, so the answer would be a=7, right and there's nothing more to that?

OpenStudy (fibonaccichick666):

yea, but I don't know what to do with those replacement sets

OpenStudy (fibonaccichick666):

i've never heard that before,

OpenStudy (anonymous):

Let me try to see if I can find anything

OpenStudy (fibonaccichick666):

@nincompoop have you heard of replacement sets?

OpenStudy (anonymous):

I'm pretty sure it just means like that a has to be one of those answers, or b has to be one of those said?

OpenStudy (fibonaccichick666):

I was thinking maybe it was a lazy way to write like 5 questions in one

OpenStudy (anonymous):

Okay, so this one, I always get confused with the negatives... Problem is 7a+21= 56

OpenStudy (anonymous):

Still be a postive right cause the 56 is bigger whensolveD?

OpenStudy (fibonaccichick666):

so you replace the coefficient with set A and the number with set B

OpenStudy (fibonaccichick666):

uhm so that one, how do you 'undo' addition?

OpenStudy (anonymous):

subtra

OpenStudy (anonymous):

7a=35

OpenStudy (anonymous):

a=5 of course lol

OpenStudy (fibonaccichick666):

yup

OpenStudy (fibonaccichick666):

medal pwease?

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